A) \[r(Cs)=1.753r(Li)\]
B) \[r(Cs)=1.936r(Li)\]
C) \[r(Cs)=2.753r(Li)\]
D) \[r(Cs)=2.936r(Li)\]
Correct Answer: C
Solution :
\[\frac{d(Cs)}{d(Li)}=\frac{1.87}{0.53}=\frac{133}{7}{{\left( \frac{r(Li)}{r(Cs)} \right)}^{3}}\] \[\frac{r(Cs)}{r(Li)}=1.753\] or \[{{r}_{Cs}}=1.753r(Li)\]
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