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Manipal Engineering Manipal Engineering Solved Paper-2013

  • question_answer
    Determine solubility of\[AgBr\]in a\[0.1\,\,M\,\,KCN\]solution.\[[{{K}_{f}}of{{[Ag{{(CN)}_{2}}]}^{-}}=5.6\times {{10}^{8}}\];\[{{K}_{sp}}\]of\[AgBr=7.7\times {{10}^{-13}}]\]

    A) \[2\times {{10}^{3}}M\]               

    B)        \[4\times {{10}^{-6}}M\]

    C) \[2\times {{10}^{-6}}M\]             

    D)        \[4\times {{10}^{-3}}M\]

    Correct Answer: A

    Solution :

    \[AgBr+2C{{N}^{-}}Ag(CN)_{2}^{-}+B{{r}^{-}}\] \[^{0.1-2s}{{K}_{sp}}={{k}_{sp}}\cdot k=4.3\times {{10}^{-4}}\] \[4.3\times {{10}^{-4}}=\left( \frac{s}{0.1-2s} \right)\]                 \[s=2\times {{10}^{-3}}\]


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