A) \[1.42\,\,eV\]
B) \[1.89\,\,eV\]
C) \[2.67\,\,eV\]
D) \[3.22\,\,eV\]
Correct Answer: D
Solution :
Based on Paulings scale \[{{(EN)}_{F}}={{(EN)}_{Cl}}=k\sqrt{\Delta }=0.208\sqrt{\Delta }\] where,\[\Delta =\]resonance energy and\[k=\]conversion factor which is 0.208 for converting\[k\,\,\,cal\]into\[eV\]. \[\Delta ={{(BE)}_{Cl-F}}-\sqrt{{{(BE)}_{Cl-Cl}}{{(BE)}_{F-F}}}\] \[=61-\sqrt{58\times 38}\] \[=61-46.95=14.05\,\,kcal\] \[{{(EN)}_{Cl}}={{(EN)}_{F}}-0.208\sqrt{\Delta }\] \[=4.0-0.208\sqrt{14.05}\] \[=4.0-0.78=3.22\,\,eV\]
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