Manipal Engineering Manipal Engineering Solved Paper-2013

  • question_answer
    \[_{7}^{14}N+_{0}^{1}n\to _{6}^{14}C+_{1}^{1}H\]is written as

    A) \[_{7}^{14}N(n,\,\,e)_{1}^{1}H\]                             

    B) \[_{7}^{14}N(p,\,\,n)_{6}^{14}C\]

    C) \[_{7}^{14}N(n,\,\,p)_{6}^{14}C\]

    D)        \[_{6}^{14}C(p,\,\,n)_{7}^{14}N\]

    Correct Answer: C

    Solution :

    \[_{7}^{14}N+_{0}^{1}n\xrightarrow{{}}_{6}^{14}C+_{1}^{1}H\] This reaction can be represented as                 \[_{7}^{14}N(n,\,\,p)_{6}^{14}C\]


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