A) \[{{r}^{3/2}}\]
B) \[r\]
C) \[{{r}^{2/3}}\]
D) \[{{r}^{1/2}}\]
Correct Answer: A
Solution :
As\[{{i}^{2}}R=hA\] \[{{l}^{2}}\left( \frac{\rho L}{\pi {{r}^{2}}} \right)=h\times 2\pi rl,\,\,l\propto {{r}^{3/2}}\]
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