Manipal Engineering Manipal Engineering Solved Paper-2013

  • question_answer
    If the work function of a potential is\[6.875\,\,eV\], its   threshold   wavelength   will   be (Take \[=c=3\times {{10}^{8}}\,m/s\])

    A) \[3600\overset{\text{o}}{\mathop{\text{A}}}\,\]                            

    B) \[2400\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[1800\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]      

    D)        \[1200\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: C

    Solution :

    \[W=\frac{hc}{\lambda }\] where\[h\]is plancks constant, \[c\]is speed of light,\[\lambda \]is wavelength                 \[\lambda =\frac{hc}{W}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{6.825\times 1.6\times {{10}^{-19}}}\]                 \[\lambda =1800\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]


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