Manipal Engineering Manipal Engineering Solved Paper-2013

  • question_answer
    \[n\] small balls, each of mass \[m\] impinge elastically each second on a surface with a velocity \[u\], then the force experienced by the surface in one second, will be

    A) \[4mnu\]                            

    B) \[2mnu\]

    C) \[1.5mnu\]        

    D)        \[0.8mnu\]

    Correct Answer: B

    Solution :

    Force experienced by the surface is equal to change in momentum in one second. From Newtons second law of motion, the rate of change of momentum of a body is equal to the external force applied on the body and the change in momentum always takes place in the direction of the force. Momentum of ball before impact\[=mu\] Momentum after impact\[=-mu\] Change in momentum\[=mu-(-mu)=2mu\] Change in momentum due to n balls in one second is\[=2mnu\]. Change of momentum = force experienced per second\[=2mnu\].


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