A) \[1.66\,\,N\]
B) \[16.6\,\,N\]
C) \[3.32\,\,N\]
D) \[33.2\,\,N\]
Correct Answer: A
Solution :
Normality,\[N=\frac{w}{E\cdot V}\] \[=\frac{10\,\,g}{60\times \frac{100}{1000}L}\] \[=1.66\,\,N\]
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