A) \[{{[\mathbf{abc}]}^{2}}\]
B) \[[\mathbf{abc}]\]
C) \[2[\mathbf{abc}]\]
D) \[3[\mathbf{abc}]\]
Correct Answer: B
Solution :
Now, \[[\mathbf{a}\,\,\mathbf{a}+\mathbf{b}\,\,\mathbf{a}+\mathbf{b}+\mathbf{c}]\] \[=[\mathbf{a}\times (\mathbf{a}+\mathbf{b})]\cdot (\mathbf{a}+\mathbf{b}+\mathbf{c})\] \[=(\mathbf{a}\times \mathbf{b})\cdot (\mathbf{a}+\mathbf{b}+\mathbf{c})=(\mathbf{a}\times \mathbf{b})\cdot \mathbf{c}\] \[=[\mathbf{a}\,\,\mathbf{b}\,\,\mathbf{c}]\]
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