A) \[72\text{ }kcal\]
B) \[28\text{ }kcal\]
C) \[-72\text{ }kcal\]
D) \[-28\text{ }kcal\]
Correct Answer: A
Solution :
\[{{N}_{2}}(g)+3{{H}_{2}}(g)2N{{H}_{3}}(g)+22\,\,kcal\] \[\because \]Activation energy for the forward reaction\[=50\,\,kcal\] \[\therefore \]Activation energy for the backward reaction \[=50+22=72\,\,kcal\]
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