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Manipal Engineering Manipal Engineering Solved Paper-2012

  • question_answer
    A compound has the molecular formula\[{{X}_{4}}{{O}_{6}}\]. If\[10g\]of\[{{X}_{4}}{{O}_{6}}\]has\[5.72\,\,g\,\,X\], then calculate atomic mass of\[X\]

    A) 32 amu                                

    B) 64 amu

    C) 67 amu                

    D)        98 amu

    Correct Answer: A

    Solution :

    Molecular weight of\[{{X}_{4}}{{O}_{6}}=(4a+96)\] \[\because \,\,(4a+96)g\,\,{{X}_{4}}{{O}_{6}}\]contains\[X=4ag\] \[\therefore \]\[10\,\,g{{X}_{4}}{{O}_{6}}\]contains\[X=\frac{4a\times 10}{4a+96}\]                                     \[5.72=\frac{4a\times 10}{4a+96}\]                 \[22.88a+549.12=40a\]                                 \[17.12a=549.12\]                                            \[a=32.07\,\,amu\]


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