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Manipal Engineering Manipal Engineering Solved Paper-2012

  • question_answer
    A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is\[340\,\,m{{s}^{-1}}\], the distance between the cliffs is

    A)  680 m                                  

    B)  1700 m

    C)  340 m                  

    D)         1620 m

    Correct Answer: C

    Solution :

    Let the distance between the two cliffs be\[d\]. Since, the man is standing midway between the two cliffs, then the distance of man from either end is\[d/2\]. The distance travelled by sound (in producing an echo)                 \[2\times \frac{d}{2}=v\times t\]    \[\Rightarrow \]   \[d=340\times 1=340\,m\]


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