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Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    A capacitor of capacitance 5\[\mu F\] is connected as shown in the figure. The internal resistance of the cell is 0.5\[\Omega \] . The amount of charge on the capacitor plate is

    A)  10 \[\Omega C\]                             

    B)  5\[\Omega C\]

    C)  6\[\Omega C\]                

    D)         10.2 \[\Omega C\]

    Correct Answer: A

    Solution :

    We know that capacitor offers infinite resistance for DC source. Current taken from the cell                 \[i=\frac{E}{R+r}\] \[\therefore \]  \[i=\frac{2.5}{1+1+0.5}=1\,\,A\] Potential drop across capacitor                 \[V=E-ir\]                 \[=2.5-1\times 0.5=2\,\,V\] The current in\[2\Omega \]resistor is zero. Charge on capacitor                 \[Q=CV\]                 \[=5\times 2=10\mu C\]


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