A) \[d\pi -d\pi \]bonding
B) \[d\pi -p\pi \]bonding
C) \[p\pi -p\pi \]bonding
D) None of the above
Correct Answer: B
Solution :
In oxyacids of chlorine,\[HClO,\,\,HCl{{O}_{2}},\,\,HCl{{O}_{3}}\] and\[HCl{{O}_{4}}\], the Central\[Cl\]atom is\[s{{p}^{3}}\] hybridized. The half filled unhybridised\[d-\]orbitals of\[Cl\]and \[p-\]orbitals of oxygen overlap to form \[\pi -\]bonds.
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