Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    The half-life of the isotope \[_{11}N{{a}^{24\,\,}}\]is 15 h. How much time does it take for \[\frac{7}{8}\] th of a sample of this isotope to decay?

    A)  75 h                                      

    B)  65 h

    C)  55 h                      

    D)         45 h

    Correct Answer: D

    Solution :

    Let initial amount be\[{{N}_{0}}\]. Remaining amount\[N={{N}_{0}}-\frac{7{{N}_{0}}}{8}=\frac{{{N}_{0}}}{8}\] \[\therefore \]  \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\Rightarrow \]               \[\frac{{{N}_{0}}}{8}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\Rightarrow \]               \[{{\left( \frac{1}{2} \right)}^{3}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\Rightarrow \]               \[n=3\] \[\therefore \]  \[\frac{t}{{{T}_{1/2}}}=3\] \[\Rightarrow \]               \[\frac{t}{15}=3\]  or  \[t=15\times 3\]                 \[t=45\,\,h\]


You need to login to perform this action.
You will be redirected in 3 sec spinner