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Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    Three blocks of masses \[{{m}_{1}},\,{{m}_{2}}\] are connected by massless strings as shown on a frictionless table. They are pulled with a force \[{{T}_{3}}\]= 40 N. If \[{{m}_{1}}=10\,kg,{{m}_{2}}=6\,kg\] and \[{{m}_{3}}=4\,kg,\] the tension \[{{T}_{2}}\]will be

    A)  20 N                                     

    B)  40 N

    C)  10 N                     

    D)         32 N

    Correct Answer: D

    Solution :

    \[{{T}_{2}}=\frac{({{m}_{1}}+{{m}_{2}}){{T}_{3}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\]                 \[=\frac{(10+6)\times 40}{10+6+4}\]                 \[=\frac{16\times 40}{20}\]                                 \[=32\,\,N\]


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