A) 750 cal
B) 630 cal
C) 1050 cal
D) 1470 cal
Correct Answer: C
Solution :
\[Q=n{{C}_{p}}\Delta T\] For hydrogen \[{{C}_{p}}=\frac{7}{2}R\] So, \[Q=n\frac{7}{2}R\Delta T\] \[=5\times \frac{7}{2}\times 2\times 30\] \[=1050\,\,cal\]
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