Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    A soap bubble in vacuum has a radius of 3 cm and another soap bubble in vacuum has a radius of 4 cm. If the two bubbles coalesce under isothermal condition, then the radius of the new bubble is

    A)  2.3 cm                 

    B)         4.5 cm

    C)  5 cm                     

    D)         7 cm

    Correct Answer: C

    Solution :

    \[r=\sqrt{r_{1}^{2}+r_{2}^{2}}=\sqrt{9+16}=\sqrt{25}=5\,\,cm\]


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