A) 2
B) 1
C) 4
D) 3
Correct Answer: C
Solution :
\[{{(17)}^{2}}=289\equiv (-1)(\bmod 5)\] \[\Rightarrow \] \[{{({{17}^{2}})}^{15}}\equiv {{(-1)}^{15}}(\bmod 5)\] \[\Rightarrow \] \[{{17}^{30}}\equiv -(\bmod 5)\] i.e., \[{{17}^{30}}\equiv 4(\bmod 5)\]
You need to login to perform this action.
You will be redirected in
3 sec
