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Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    If\[\frac{2x+3}{(x+1)(x-3)}=\frac{a}{x+1}+\frac{b}{x-3}\]then\[a+b\]is equal to

    A) \[1\]

    B) \[2\]

    C) \[9/4\]

    D) \[-1/4\]

    Correct Answer: B

    Solution :

    \[\therefore \]\[(2x+3)=a(x-3)+b(x+1)\] Put\[x=-1\]and\[x=3\]respectively, we get                 \[1=-4a\]and \[9=4b\] \[\Rightarrow \,\,\,a=-\frac{1}{4}\] and \[b=\frac{9}{4}\] \[\therefore \]  \[a+b=-\frac{1}{4}+\frac{9}{4}=2\]


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