2. Solved Papers
  3. Manipal Engineering

Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    For a cell reaction involving a two electron change, the standard emf of the cell is found to be\[0.295\,\,V\]at\[{{25}^{o}}C\]. The equilibrium constant of the reaction at\[{{25}^{o}}C\]will be

    A) \[10\]                                   

    B)                        \[1\times {{10}^{10}}\]

    C)                        \[1\times {{10}^{-10}}\]               

    D)                        \[10\times {{10}^{-2}}\]

    Correct Answer: B

    Solution :

        \[\Delta {{G}^{o}}=-nFE{}^\circ \]     \[\Delta G{}^\circ =-2.303RT\log {{K}_{c}}\]   \[nFE{}^\circ =2.303RT\log {{K}_{c}}\] \[\log {{K}_{c}}=\frac{nFE{}^\circ }{2.303RT}=\frac{2\times 96500\times 0.295}{2.303\times 8.314\times 298}\] \[\log {{K}_{c}}=9.97\]       \[{{K}_{c}}=1\times {{10}^{10}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner