A) 15
B) 18
C) 36
D) 12
Correct Answer: D
Solution :
Given sides of a triangle are \[a=30,\,\,b=24,\,\,c=18\] \[\therefore \] \[s=\frac{a+b+c}{2}\] \[\frac{30+24+18}{2}=36\] Now, \[\Delta =\sqrt{s(s-a)(s-b)(s-c)}\] \[=\sqrt{36(36-30)(36-24)(36-18)}\] \[=\sqrt{36\times 6\times 12\times 18}\] \[=\sqrt{36\times 36\times 36}=216\] \[\therefore \] \[{{r}_{3}}=\frac{\Delta }{s-c}=\frac{216}{18}=12\]
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