A) 2, 1
B) 1, 2
C) 3, 2
D) 2, 3
Correct Answer: A
Solution :
Let the equation of parabola whose axis is\[x-\]axis, is \[{{y}^{2}}=\pm 4a(x-h)\] On differentiating w.r.t. x, we get \[2y{{y}_{1}}=\pm \,4a\] \[\Rightarrow \] \[y{{y}_{1}}=\pm 2a\] Again differentiating, we get \[{{({{y}_{1}})}^{2}}+y{{y}_{2}}=0\] Hence, order and degree are respectively 1 and 2.
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