A) \[\frac{20}{80}\]
B) \[\frac{80}{20}\]
C) \[\frac{34}{77}\]
D) \[\frac{77}{68}\]
Correct Answer: C
Solution :
Mole fraction of\[{{H}_{2}}O=\frac{80/18}{\frac{80}{18}+\frac{20}{34}}=\frac{34}{77}\]
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