A) \[3\times {{10}^{20}}\]
B) \[3\times {{10}^{19}}\]
C) \[6\times {{10}^{20}}\]
D) \[6\times {{10}^{19}}\]
Correct Answer: A
Solution :
\[i=1.6\,\,A,\,\,t=1\]minute\[=60\,\,s\] Charge on one\[C{{u}^{++}}=2e\] Let\[n\,\,C{{u}^{++}}\]are liberated from \[Q=ne\] \[it=n(2e)\] \[1.6\times 60=n(2\times 1.6\times {{10}^{-19}})\] \[n=3\times {{10}^{20}}\,\,ions\]
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