A) 5.5 km/s
B) 11 km/s
C) 16.5 km/s
D) 22 km/s
Correct Answer: D
Solution :
Escape velocity\[{{v}_{e}}=\sqrt{\frac{2GM}{R}}\] \[=R\sqrt{\frac{8}{3}G\rho }\] \[\therefore \,\,\,\,\,\,\,\,\,v\propto R\] We can say, if radius of a planet is double than that of earth then escape velocity from this planet will be\[22\,\,km/s\].
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