A) 2.5 W
B) 5 W
C) 10 W
D) 104 W
Correct Answer: A
Solution :
Given,\[V=100\,\,\sin \,\,100t\] \[i=100\,\,\sin \left( 100t+\frac{\pi }{3} \right)\] Comparing with standard forms \[V={{V}_{0}}\sin \omega t\] \[I={{I}_{0}}\sin (\omega t+\phi )\] \[\therefore \] \[{{V}_{0}}=100\,\,V\] \[{{I}_{0}}=100\,\,mA=100\times {{10}^{-3}}A\] \[\phi =\frac{\pi }{3}\] Power \[P=\frac{{{V}_{0}}{{I}_{0}}}{2}\cos \phi \] \[\therefore \] \[P=\frac{100\times 100\times {{10}^{-3}}}{2}\cos \frac{\pi }{2}=2.5\,\,W\]
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