A) \[Zn\]will reduce\[F{{e}^{2+}}\]
B) \[Zn\]will reduce\[M{{g}^{2+}}\]
C) \[Mg\]oxidizes\[Fe\]
D) \[Zn\]oxidizes\[Fe\]
Correct Answer: A
Solution :
Higher the negative value of\[E{}^\circ \], more is the reducing power. The order of\[E{}^\circ \]values (negative value) is \[-\underset{(Mg)}{\mathop{2.37}}\,>-\underset{(Zn)}{\mathop{0.76}}\,>\underset{(Fe)}{\mathop{-0.44}}\,\] \[\therefore \]\[Mg\]can reduce both\[Z{{n}^{2+}}\]and\[F{{e}^{2+}}\].\[Zn\]can reduce\[F{{e}^{2+}}\], but not\[M{{g}^{2+}}\]. Fe cannot reduce \[Mg\]and\[~Zn\]but can oxidize them.
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