A) \[CoC{{l}_{3}}\cdot 4N{{H}_{3}}\]and\[PtC{{l}_{4}}\cdot 4N{{H}_{3}}\]
B) \[CoC{{l}_{3}}\cdot 3N{{H}_{3}}\]and\[PtC{{l}_{4}}\cdot 5N{{H}_{3}}\]
C) \[CoC{{l}_{3}}\cdot 6N{{H}_{3}}\]and\[PtC{{l}_{4}}\cdot 5N{{H}_{3}}\]
D) \[CoC{{l}_{3}}\cdot 6N{{H}_{3}}\]and\[PtC{{l}_{4}}\cdot 3N{{H}_{3}}\]
Correct Answer: A
Solution :
\[C{{o}^{3+}}\]and\[P{{t}^{4+}}\]have 6 coordination number. \[CoC{{l}_{3}}\cdot 6N{{H}_{3}}\]and\[PtC{{l}_{4}}\cdot 5N{{H}_{3}}\] \[[Co(N{{H}_{3}})]C{{l}_{3}}\xrightarrow{In\,\,solution}{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}+3C{{l}^{-}}\] \[[PtCl{{(N{{H}_{3}})}_{5}}]C{{l}_{3}}\xrightarrow{In\,\,solution}\] \[{{[PtCl{{(N{{H}_{3}})}_{5}}]}^{3+}}+3C{{l}^{-}}\] Number of ionic species are same in the solution of both complexes, therefore their equimolar solutions will show same conductance.
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