A) 30 rad
B) \[8\times {{10}^{-4}}\] rad
C) 12 rad
D) 70.5 rad
Correct Answer: B
Solution :
Angular width\[\theta =\frac{\beta }{D}\] \[=\frac{\lambda }{d}=\frac{4800\times {{10}^{-10}}}{0.6\times {{10}^{-3}}}\] \[=8\times {{10}^{-4}}\,\,rad\]You need to login to perform this action.
You will be redirected in
3 sec