Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    To the lines\[a{{x}^{2}}+2hxy+b{{y}^{2}}=0\]the lines \[{{a}^{2}}{{x}^{2}}+2h(a+b)xy+{{b}^{2}}{{y}^{2}}=0\], are

    A)  equally inclined

    B)  perpendicular

    C)  bisector of the angle

    D)  None of the above

    Correct Answer: A

    Solution :

    If the two pairs of straight lines have the same bisectors, then the two pairs are equally inclined. The equation of the bisectors of the angle between     the     lines     given     by \[a{{x}^{2}}+2hxy+b{{y}^{2}}=0\]is                 \[\frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{xy}{h}\]                                   ? (i) The equation of the bisectors of the angle between the lines given by                 \[{{a}^{2}}{{x}^{2}}+2h(a+b)xy+{{b}^{2}}{{y}^{2}}=0\]is \[\Rightarrow \]               \[\frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{xy}{h}\]                                   ? (ii) Clearly Eqs. (i) and (ii) are the same. The two pairs of straight lines are equally inclined.


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