Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    The least number of times a fair coin must be tossed so that the probability of getting at least one head is at least 0.8 is

    A)  7                                            

    B)  6

    C)  5                            

    D)         3

    Correct Answer: D

    Solution :

    Suppose the coin is tossed\[n\]times. Let\[X\]be the number of the heads obtained. Then,\[X\]follows a binomial distribution with parameters\[n\]and\[p=\frac{1}{2}\] Now,     \[P(X\ge 1)\ge 0.8\Rightarrow 1-P(X=0)\ge 0.8\] \[\Rightarrow \]               \[1{{-}^{n}}{{C}_{0}}{{p}^{0}}{{(1-p)}^{n}}\ge 0.8\] \[\Rightarrow \]               \[{{\left( \frac{1}{2} \right)}^{n}}\le 0.2\]or\[{{\left( \frac{1}{2} \right)}^{n}}\le \frac{1}{5}\] \[\Rightarrow \]               \[{{2}^{n}}\ge 5\] \[\Rightarrow \]               \[n\ge 3\] Hence, the least value of\[n\]is 3.


You need to login to perform this action.
You will be redirected in 3 sec spinner