Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    A sounding source of frequency 500 Hz moves towards a stationary observer with a velocity 30 m/s. If the velocity of sound in air is 330 m/s, find the frequency beared by the observer.

    A)  500 Hz                                 

    B)  550 Hz

    C)  355 Hz                 

    D)         55.5 Hz

    Correct Answer: B

    Solution :

    \[\begin{align}   & \text{}\xrightarrow{{{\text{v}}_{\text{s}}}\text{=30}\,\,\text{m/s}}\,\,\,\,\,\,\,\underset{{{v}_{o}}=0}{\mathop{\text{Observer}}}\, \\  & \text{Source} \\ \end{align}\] Here,\[n=500\,\,Hz,\,\,{{v}_{o}}=0\] \[{{v}_{s}}=30\,\,m/s,\,\,v=330\,\,m/s\] \[\therefore \]From,      \[n=n\left( \frac{v-{{v}_{o}}}{v-{{v}_{s}}} \right)\]                                 \[=500\left( \frac{330}{330-30} \right)\]                                 \[=550\,\,Hz\]


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