A) \[{{(P+1)}^{n}}-1\]
B) \[{{P}^{n}}-1\]
C) \[{{(P+1)}^{n-1}}-1\]
D) None of these
Correct Answer: A
Solution :
Number of selections of any number of copies of a book\[=P+1\], (because copies of the same book are identical things). Similarly, for each book. \[\therefore \] Total number of selections \[=(P+1)(P+1)...\]... to\[n\]factors \[={{(P+1)}^{n}}\] But this includes a selections which is empty ie, zero copy of each is selected. Excluding this, the required number of non-empty selections \[={{(P+1)}^{n}}-1\]
You need to login to perform this action.
You will be redirected in
3 sec
