A) 30 min
B) 15 min
C) 7.5 min
D) 60 min
Correct Answer: A
Solution :
\[{{T}_{50}}=50\,\,\min \] \[k=\frac{2.303\log 2}{{{T}_{50}}}=\frac{2.303\log 2}{15}\] \[a=0.1\,\,M\] \[(a-x)=0.025\,\,M\] For first order reaction, \[k=\frac{2.303}{t}\log \left( \frac{a}{a-x} \right)\] \[\frac{2.303\log 2}{15}=\frac{2\times 2.303}{t}.\log \frac{0.1}{0.025}\] \[=\frac{2.303}{t}\log 4\] \[\therefore \] \[\frac{2.303\log 2}{15}=\frac{2\times 2.303\log 2}{t}\] \[\therefore \]\[t=30\,\,\min \]
You need to login to perform this action.
You will be redirected in
3 sec
