A) \[H{{e}^{2+}}\]
B) \[{{H}^{+}}\]
C) \[H{{e}^{+}}\]
D) \[{{D}^{+}}\]
Correct Answer: B
Solution :
\[e/m\]ratio for\[H{{e}^{2+}}=\frac{2}{4}\] \[e/m\]ratio for\[{{H}^{+}}=\frac{1}{1}\] \[e/m\]ratio for\[H{{e}^{+}}=\frac{1}{4}\] \[e/m\]ratio for\[{{D}^{+}}=\frac{1}{2}\] \[\therefore \]The\[e/m\]is highest for hydrogen.
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