A) \[3\,\,g\]atoms of\[C{{O}_{2}}\]
B) \[18.1\times {{10}^{23}}\]molecules of\[C{{O}_{2}}\]
C) \[6.02\times {{10}^{23}}\]atoms of\[O\]
D) \[6.02\times {{10}^{23}}\]atoms of\[C\]
Correct Answer: D
Solution :
One mole\[=6.02\times {{10}^{23}}\]molecules/atoms/ions. \[\because \]\[C{{O}_{2}}\]molecule has one\[C\]and two oxygen atoms. \[\therefore \]contains\[6.023\times {{10}^{23}}\]atoms of\[C\]and \[6.023\,\times {{10}^{23}}\] molecules of \[{{O}_{2}}\].
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