| I.\[PhCOOH\] |
| II.\[o-N{{O}_{2}}{{C}_{6}}{{H}_{4}}COOH\] |
| III.\[p-N{{O}_{2}}{{C}_{6}}{{H}_{4}}COOH\] |
| IV.\[m-N{{O}_{2}}{{C}_{6}}{{H}_{4}}COOH\] |
A) \[I>II>III>IV\]
B) \[II>IV>III>I\]
C) \[II>IV>I>III\]
D) \[II>III>IV>I\]
Correct Answer: D
Solution :
\[-N{{O}_{2}}\]group at any position shows electron withdrawing effect, thus acid strength is increased. But \[o-\]nitro benzoic acid believed to have ortho effect. As a result, resonance gets...prevented. Hence, its acid strength is maximum, thus, the order of acid strength (II) < (III) > (IV) > (I) (The effect is more at para position than meta.)
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