A) ethene
B) ethane
C) ethyl nitrile
D) nitro ethane
Correct Answer: D
Solution :
\[{{C}_{2}}{{H}_{5}}Br+AgN{{O}_{2}}(alc.)\to \underset{nitro\,\,ethane}{\mathop{{{C}_{2}}{{H}_{5}}N{{O}_{2}}}}\,+AgBr\]
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