A) \[{{[Fe{{(CN)}_{6}}]}^{4-}}\]
B) \[{{[Mn{{(CN)}_{6}}]}^{4-}}\]
C) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
D) \[{{[Ni{{(N{{H}_{3}})}_{6}}]}^{2+}}\]
Correct Answer: D
Solution :
The complex in which nd orbitals are used in hybridisation, are called outer orbital complex. (a)\[{{[Fe{{(CN)}_{6}}]}^{4-}}=\] (b)\[{{[Mn{{(CN)}_{6}}]}^{4-}}=\] (c)\[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}=\] (d)\[{{[Ni{{(N{{H}_{3}})}_{6}}]}^{2+}}=\]You need to login to perform this action.
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