Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    The standard emf of a cell involving one electron change is found to be\[0.591V\]at\[{{25}^{o}}C\]. The equilibrium constant of the reaction is \[(F=96,500\,\,C\,\,mo{{l}^{-1}})\]

    A) \[1.0\times {{10}^{1}}\]                

    B) \[1.0\times {{10}^{5}}\]

    C) \[1.0\times {{10}^{10}}\]             

    D)        \[1.0\times {{10}^{30}}\]

    Correct Answer: C

    Solution :

    \[E{{{}^\circ }_{cell}}=\frac{2.303RT}{nF}\times \log {{K}_{eq}}\]                                \[E{{{}^\circ }_{cell}}=\frac{0.0591}{n}\log {{K}_{eq}}\]   \[(At\,\,298\,\,K)\]                 \[0.591=\frac{0.0591}{1}\log {{K}_{eq}}\] \[\therefore \]  \[\log {{K}_{eq}}=10\] \[\therefore \]  \[{{K}_{eq}}=1\times {{10}^{10}}\]


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