A) \[\frac{2}{3}g\]
B) g
C) \[\frac{1}{3}g\]
D) Zero
Correct Answer: C
Solution :
If man slides down with some acceleration, then its apparent weight decreases. For critical condition rope can bear only\[2/3\]of his weight. If\[a\]is the minimum acceleration, then tension in the rope\[=m(g-a)\] = breaking strength \[\Rightarrow \] \[m(g-a)=\frac{2}{3}mg\] \[\Rightarrow \] \[a=g-\frac{2g}{3}=\frac{g}{3}\]You need to login to perform this action.
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