A) \[\frac{3{{A}_{0}}}{4}\]
B) \[{{A}_{0}}\]
C) 4\[{{A}_{0}}\]
D) 12\[{{A}_{0}}\]
Correct Answer: A
Solution :
Torque\[\overset{\to }{\mathop{\tau }}\,=\frac{\overset{\to }{\mathop{dL}}\,}{dt}=\frac{{{L}_{2}}-{{L}_{1}}}{\Delta t}=\frac{4{{A}_{0}}-{{A}_{0}}}{4}=\frac{3{{A}_{0}}}{4}\]You need to login to perform this action.
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