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Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    The force of interaction between two charges \[{{q}_{1}}=6\mu C\]and \[{{q}_{2}}=2\mu C\] N. If charge \[q=-2\mu C\] is added to each of the charges, then the new force of interaction is

    A)  \[2\times {{10}^{-7}}N\]                             

    B)  Zero

    C)  30 N                     

    D)         \[2\times {{10}^{-3}}N\]

    Correct Answer: B

    Solution :

    New force\[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{(6-2)(2-2)}{{{r}^{2}}}\times {{10}^{-12}}\]                 \[=0\]


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