Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    A bomb of mass 9 kg explodes into two parts. One part of mass 3 kg moves with velocity 16 m/s, then the KE of the other part is

    A)  162 J                                    

    B)  150 J

    C)  192 J                    

    D)         200 J

    Correct Answer: C

    Solution :

    From the law of conservation of momentum \[3\times 16+6\times v=9\times 0\] or            \[v=-8m/s\] \[\Rightarrow \]               \[v=8m/s\]      (numerically) Therefore, its kinetic energy                 \[K=\frac{1}{2}\times 6\times {{(8)}^{2}}=192\,\,J\]


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