Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    A bullet comes out of the barrel of gun of length 2 m with a speed 80 m/s. The average acceleration of the bullet is

    A)  \[1.6\,m/{{s}^{2}}\]                                      

    B)  \[160\,\,m/{{s}^{2}}\]

    C)  \[1600\,\,m/{{s}^{2}}\]                

    D)         \[16\,\,m/{{s}^{2}}\]

    Correct Answer: C

    Solution :

    Given,\[s=2m,\,\,u=80\,\,m/s,\,\,v=0\] From     \[{{v}^{2}}={{u}^{2}}-2as\] \[\therefore \]  \[{{(0)}^{2}}={{(80)}^{2}}-2\times a\times 2\] or            \[a=\frac{80\times 80}{4}=1600\,\,m/{{s}^{2}}\]


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