Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    Two pendulums have time periods T and 5T/4. They start SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?

    A) \[45{}^\circ \]                                   

    B) \[90{}^\circ \]

    C) \[60{}^\circ \]                                   

    D) \[30{}^\circ \]

    Correct Answer: B

    Solution :

    When bigger pendulum of time period\[\frac{5T}{4}\]completes one vibration, the smaller pendulum will complete\[\left( \frac{5}{4} \right)\]vibrations. It means the smaller pendulum will be leaded the bigger pendulum by phase\[\frac{T}{4}\sec =\frac{\pi }{2}rad={{90}^{o}}\].


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