A) 0.05 J
B) 50 J
C) 0.50 J
D) 500 J
Correct Answer: A
Solution :
Induced emf produced in coil \[e=\frac{-d\phi }{dt}=\frac{-d}{dt}(BA)\] \[\therefore \] \[\left| e \right|=A\frac{dB}{dt}=0.01\times \frac{1}{1\times {{10}^{-3}}}\] \[\left| e \right|=10\,\,V\] Current produced in coil, \[i=\frac{\left| e \right|}{R}=\frac{10}{2}=5\,\,A\] Heat evolved\[={{i}^{2}}Rt={{(5)}^{2}}\times (2)\times 1\times {{10}^{-3}}\] \[=0.05\,\,J\]
You need to login to perform this action.
You will be redirected in
3 sec
