A) 10 V
B) \[5\sqrt{3}v\]
C) 5V
D) 1V
Correct Answer: B
Solution :
\[E={{E}_{0}}\cos \omega t=10\cos (2\pi \times ft)\] \[=10\cos \left( 2\pi \times 50\times \frac{1}{600} \right)\] \[=10\cos \left( \frac{\pi }{6} \right)=10\times \frac{\sqrt{3}}{2}=5\sqrt{3}\,\,V\]You need to login to perform this action.
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