Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    A transistor is working in common emitter mode. Its amplification factor (\[\beta \]) is 80. If the base current is 250\[\mu A\], the collector current will be

    A)  1.25\[\mu A\]                                  

    B)  \[\frac{250}{80}\mu A\]

    C)  430\[\mu A\]                   

    D)         \[250\times 80\,\mu A\]

    Correct Answer: D

    Solution :

    Current amplification-factor,\[\beta =\frac{{{i}_{C}}}{{{i}_{B}}}\] \[\therefore \]                                  \[{{i}_{C}}={{i}_{\beta }}\times \beta \]                                                 \[=250\times 80\mu A\]


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